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7^(3x+1)=1/49
We move all terms to the left:
7^(3x+1)-(1/49)=0
We add all the numbers together, and all the variables
7^(3x+1)-(+1/49)=0
We get rid of parentheses
7^(3x+1)-1/49=0
We multiply all the terms by the denominator
(7^(3x+1))*49-1=0
We move all terms containing x to the left, all other terms to the right
(7^(3x+1))*49=1
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